Howard Florey
(1898-1968)

Howard Walter Florey 1945
Howard Walter Florey 1945 Sir Howard Walter Florey, Nobel Prize in Medicine 1945 Foto: Nobel Foundation / Public Domain

Australian pathologist (1898-1968) – Howard Florey was born in Adelaide (Capital city of South Australia) on September 24th, 1898 and died in Oxford (City in Oxfordshire, England) on February 21st, 1968 at the age of 69. Today Howard Florey would be 125 years old.

Age

how old was Howard Florey when he died?

69

Howard Florey died in 1968 at the age of 69.


Biographical data

Birthday September 24th, 1898 (Saturday)
Place of Birth Adelaide
Capital city of South Australia
Death Date February 21st, 1968 (Wednesday)
Death place Oxford
City in Oxfordshire, England
Birth sign (Zodiac) Libra (The Scales) ♎
Chinese Zodiac Dog 狗

Other personalities born on September 24

Also born in 1898

Howard Florey

Birthday

When was Howard Florey born?

Howard Florey was born on September 24th, 1898.

Death

When did Howard Florey die?

Howard Florey died on February 21st, 1968 at the age of 69 in Oxford (City in Oxfordshire, England). Today Howard Florey would be 125 years old.

Place of Birth

Where was Howard Florey born?

Adelaide (Capital city of South Australia).

Death place

Where did Howard Florey die?

Oxford (City in Oxfordshire, England).

Zodiac

What is the zodiac sign of Howard Florey?

Howard Florey was born in the zodiac sign Libra (The Scales).

Chinese Zodiac

Which Chinese zodiac sign does Howard Florey have?

Howard Florey was born in 1898 in the year of the Chinese zodiac Dog.

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Died on February 21st, 1968:
Anniversaries of death

Australian pathologist (1898-1968)

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