March 29th, 1368 was a Tuesday.
People born on March 29th, 1368 (assuming the person is still alive) would have turned 656 years old this year (2024).
March 21st, 1368 - April 20th, 1368
Why not celebrate an alternative birthday? In 306 days, exactly on May 4th, 2025, people who were born on March 29th, 1368 will be 240,000 days old!
German writer and scholar
*March 29th, 1911, Cologne †January 1st, 2010, NorwichPresident of the United States from 1841 to 1845
*March 29th, 1790, Greenway Plantation †January 18th, 1862, RichmondSouth Korean singer and actress (1994-2019)
*March 29th, 1994, Haeundae District †October 14th, 2019, Sujeong-suGerman engineer and naval officer
*March 29th, 1916, Büdelsdorf †October 13th, 2023, BornheimEnglish noble and admiral
*March 29th, 1395, Devon †August 5th, 1447, StepneyFrench writer (1920-2007)
*March 29th, 1920, Fressines †March 6th, 2007, 6th arrondissement of ParisBritish actor (1925-2012)
*March 29th, 1925, Cliftonville †January 30th, 2012, MitchamItalian actor, film director, screenwriter and film producer
*March 29th, 1939, VeniceBrazilian-American singer and songwriter (1940–2023)
*March 29th, 1940, Salvador †June 5th, 2023, PhiladelphiaAmerican actor (1889–1951)
*March 29th, 1889, Columbus †May 7th, 1951, Beverly HillsGerman socialist and political activist
*March 29th, 1826, Giessen †August 7th, 1900, CharlottenburgAmerican actress (1919–2001)
*March 29th, 1919, Columbus †December 31st, 2001, NorwalkGenevan theologian and biblical scholar (1657-1736)
*March 29th, 1657, Geneva †January 8th, 1736, AmsterdamAustralian model, actress, businesswoman and philanthropist
*March 29th, 1964, KillaraSpanish composer (1647-1706)
*March 29th, 1647, Rubielos de Mora †November 4th, 1706, ValenciaFixed holidays (Christian feast day) which are celebrated on March 29th.
M = 1000 | C = 100 | L = 50 | X = 10 | IX = 9 | V = 5 | I = 1 |
Yes: 1368 is a leap year, therefore has a 29th of February with an additional leap day and a total of 366 days (instead of the usual 365 days in a normal year).