August 2nd, 1735 was a Tuesday.
July 23rd, 1735 - August 23rd, 1735
Why not celebrate an alternative birthday? In 773 days, exactly on July 16th, 2028, people who were born on August 2nd, 1735 will be 107,000 days old!
President of the United States from 1797 to 1801
*October 30th, 1735, Braintree †July 4th, 1826, QuincyGerman composer (1735–1782)
*September 5th, 1735, Leipzig †January 1st, 1782, London(1735-1796)
*August 3rd, 1735, Hanau †December 18th, 1796, Steinau an der StraßeAmerican silversmith and Patriot in the American Revolution
*January 1st, 1735, Boston †May 10th, 1818, BostonFrench soldier (1735-1820)
*May 28th, 1735, Strasbourg †September 23rd, 1820, ParisGerman Geheimrat (1735-1801)
*August 6th, 1735, Powidzko †January 9th, 1801, BerlinAmerican politician (1735-1792)
*November 8th, 1735, Sotterley †February 10th, 1792, AnnapolisBritish politician and army officer (1735-1806)
*February 22nd, 1735, London †December 29th, 1806, Goodwood HouseGerman composer
*February 25th, 1735, Grossenbehringen †December 1st, 1792, WeimarSchweizer Mäzenin (1735-1820)
*July 20th, 1735, Lyon †May 11th, 1820, TrogenAmerican politician (1735-1791)
*April 13th, 1735, Piscataway †July 25th, 1791, Isle of WightDanish architect (1735-1799)
*May 26th, 1735, Copenhagen †May 24th, 1799, CopenhagenPrincess of Saxony and an Abbess
*February 12th, 1735, Warsaw †November 19th, 1782, Château de BrumathGerman princess (1735-1791)
*June 24th, 1735, Coburg †February 18th, 1791, UnterschwaningenFixed holidays (Christian feast day, Romani genocide-related observances, including) which are celebrated on August 2nd.
| M = 1000 | D = 500 | C = 100 | X = 10 | V = 5 | I = 1 |
No: With 365 days 1735 is a normal year and no leap year.