Abe Attell
(1884-1970)

American boxer – Abe Attell was born in San Francisco (Consolidated city and county in California, United States) on February 22nd, 1884 and died in New Paltz (Village in New York) on February 7th, 1970 at the age of 85. Today Abe Attell would be 140 years old.

Age

how old was Abe Attell when he died?

85

Abe Attell died in 1970 at the age of 85.


Biographical data

Birthday February 22nd, 1884 (Friday)
Place of Birth San Francisco
Consolidated city and county in California, United States
Death Date February 7th, 1970 (Saturday)
Death place New Paltz
Village in New York
Birth sign (Zodiac) Pisces (The Fish) ♓
Chinese Zodiac Monkey 猴

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Also born in 1884

Abe Attell

Birthday

When was Abe Attell born?

Abe Attell was born on February 22nd, 1884.

Death

When did Abe Attell die?

Abe Attell died on February 7th, 1970 at the age of 85 in New Paltz (Village in New York). Today Abe Attell would be 140 years old.

Place of Birth

Where was Abe Attell born?

San Francisco (Consolidated city and county in California, United States).

Death place

Where did Abe Attell die?

New Paltz (Village in New York).

Zodiac

What is the zodiac sign of Abe Attell?

Abe Attell was born in the zodiac sign Pisces (The Fish).

Chinese Zodiac

Which Chinese zodiac sign does Abe Attell have?

Abe Attell was born in 1884 in the year of the Chinese zodiac Monkey.

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Died on February 7th, 1970:
Anniversaries of death

American boxer

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