Adrian Rollini
(1903-1956)

American jazz musician – Adrian Rollini was born in New York City (Most populous city in the United States) on June 28th, 1903 and died in Homestead (City in Miami-Dade County, Florida, United States) on May 15th, 1956 at the age of 52. Today Adrian Rollini would be 120 years old.

Age

how old was Adrian Rollini when he died?

52

Adrian Rollini died in 1956 at the age of 52.


Biographical data

Birthday June 28th, 1903 (Sunday)
Place of Birth New York City
Most populous city in the United States
Death Date May 15th, 1956 (Tuesday)
Death place Homestead
City in Miami-Dade County, Florida, United States
Birth sign (Zodiac) Cancer (The Crab) ♋
Chinese Zodiac Rabbit 兔

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Also born in 1903

Adrian Rollini

Birthday

When was Adrian Rollini born?

Adrian Rollini was born on June 28th, 1903.

Death

When did Adrian Rollini die?

Adrian Rollini died on May 15th, 1956 at the age of 52 in Homestead (City in Miami-Dade County, Florida, United States). Today Adrian Rollini would be 120 years old.

Place of Birth

Where was Adrian Rollini born?

New York City (Most populous city in the United States).

Death place

Where did Adrian Rollini die?

Homestead (City in Miami-Dade County, Florida, United States).

Zodiac

What is the zodiac sign of Adrian Rollini?

Adrian Rollini was born in the zodiac sign Cancer (The Crab).

Chinese Zodiac

Which Chinese zodiac sign does Adrian Rollini have?

Adrian Rollini was born in 1903 in the year of the Chinese zodiac Rabbit.

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Died on May 15th, 1956:
Anniversaries of death

American jazz musician

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