American politician – Albert C. Howard was born in Cranston (City in Providence County, Rhode Island, United States) on February 29th, 1828 and died in on July 3rd, 1910 at the age of 82. Today Albert C. Howard would be 196 years old.
Albert C. Howard died in 1910 at the age of 82.
Birthday | February 29th, 1828 (Friday) |
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Place of Birth | Cranston City in Providence County, Rhode Island, United States |
Death Date | July 3rd, 1910 (Sunday) |
Birth sign (Zodiac) | Pisces (The Fish) ♓ |
Chinese Zodiac | Rat 鼠 |
Albert C. Howard was born on February 29th, 1828.
Albert C. Howard died on July 3rd, 1910 at the age of 82 in . Today Albert C. Howard would be 196 years old.
Cranston (City in Providence County, Rhode Island, United States).
Albert C. Howard was born in the zodiac sign Pisces (The Fish).
Albert C. Howard was born in 1828 in the year of the Chinese zodiac Rat.