Alfred Redl
(1864-1913)

Austro-Hungarian army officer – Alfred Redl was born in Lviv (Capital city of Lviv Oblast in western Ukraine) on March 14th, 1864 and died in Vienna (Capital of and state in Austria) on May 25th, 1913 at the age of 49. Today Alfred Redl would be 160 years old.

Age

how old was Alfred Redl when he died?

49

Alfred Redl died in 1913 at the age of 49.


Biographical data

Birthday March 14th, 1864 (Monday)
Place of Birth Lviv
Capital city of Lviv Oblast in western Ukraine
Death Date May 25th, 1913 (Sunday)
Death place Vienna
Capital of and state in Austria
Birth sign (Zodiac) Pisces (The Fish) ♓
Chinese Zodiac Rat 鼠

Other personalities born on March 14

Also born in 1864

Alfred Redl

Birthday

When was Alfred Redl born?

Alfred Redl was born on March 14th, 1864.

Death

When did Alfred Redl die?

Alfred Redl died on May 25th, 1913 at the age of 49 in Vienna (Capital of and state in Austria). Today Alfred Redl would be 160 years old.

Place of Birth

Where was Alfred Redl born?

Lviv (Capital city of Lviv Oblast in western Ukraine).

Death place

Where did Alfred Redl die?

Vienna (Capital of and state in Austria).

Zodiac

What is the zodiac sign of Alfred Redl?

Alfred Redl was born in the zodiac sign Pisces (The Fish).

Chinese Zodiac

Which Chinese zodiac sign does Alfred Redl have?

Alfred Redl was born in 1864 in the year of the Chinese zodiac Rat.

Alfred Redl: Future birthdays

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Died on May 25th, 1913:
Anniversaries of death

Austro-Hungarian army officer

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