Arata Takebe (56)
July 20th, 1970
Japanese politician – Arata Takebe was born in Shari (Town in Shari district, Hokkaidō, Japan) on July 20th, 1970 and is 56 years old today.
Age
How old is Arata Takebe?
56
Arata Takebe is 56 years old.
Biographical data
| Birthday | July 20th, 1970 (Monday) |
|---|---|
| Place of Birth | Shari Town in Shari district, Hokkaidō, Japan |
| Birth sign (Zodiac) | Cancer (The Crab) ♋ |
| Chinese Zodiac | Dog 狗 |
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Arata Takebe
Birthday
When was Arata Takebe born?
Arata Takebe was born on July 20th, 1970.
Place of Birth
Where was Arata Takebe born?
Shari (Town in Shari district, Hokkaidō, Japan).
Zodiac
What is the zodiac sign of Arata Takebe?
Arata Takebe was born in the zodiac sign Cancer (The Crab).
Chinese Zodiac
Which Chinese zodiac sign does Arata Takebe have?
Arata Takebe was born in 1970 in the year of the Chinese zodiac Dog.
Arata Takebe: Future birthdays
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