August Howaldt
(1838-1868)

German sculptor (1838-1868) – August Howaldt was born in Brunswick (City in Lower Saxony, Germany) on September 28th, 1838 and died in Sankt Andreasberg (District of Braunlage, Germany) on July 4th, 1868 at the age of 29. Today August Howaldt would be 187 years old.

Age

how old was August Howaldt when he died?

29

August Howaldt died in 1868 at the age of 29.


Biographical data

Birthday September 28th, 1838 (Friday)
Place of Birth Brunswick
City in Lower Saxony, Germany
Death Date July 4th, 1868 (Saturday)
Death place Sankt Andreasberg
District of Braunlage, Germany
Birth sign (Zodiac) Libra (The Scales) ♎
Chinese Zodiac Dog 狗

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August Howaldt

Birthday

When was August Howaldt born?

August Howaldt was born on September 28th, 1838.

Death

When did August Howaldt die?

August Howaldt died on July 4th, 1868 at the age of 29 in Sankt Andreasberg (District of Braunlage, Germany). Today August Howaldt would be 187 years old.

Place of Birth

Where was August Howaldt born?

Brunswick (City in Lower Saxony, Germany).

Death place

Where did August Howaldt die?

Sankt Andreasberg (District of Braunlage, Germany).

Zodiac

What is the zodiac sign of August Howaldt?

August Howaldt was born in the zodiac sign Libra (The Scales).

Chinese Zodiac

Which Chinese zodiac sign does August Howaldt have?

August Howaldt was born in 1838 in the year of the Chinese zodiac Dog.

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Died on July 4th, 1868:
Anniversaries of death

German sculptor (1838-1868)

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