American politician (1813-1909) – Frederick Holbrook was born in East Windsor (Town of Connecticut, United States) on February 15th, 1813 and died in Brattleboro (Town in Windham County, Vermont, United States) on April 28th, 1909 at the age of 96. Today Frederick Holbrook would be 211 years old.
Frederick Holbrook died in 1909 at the age of 96.
Birthday | February 15th, 1813 (Monday) |
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Place of Birth | East Windsor Town of Connecticut, United States |
Death Date | April 28th, 1909 (Wednesday) |
Death place | Brattleboro Town in Windham County, Vermont, United States |
Birth sign (Zodiac) | Aquarius (The Water-Bearer) ♒ |
Chinese Zodiac | Rooster 雞 |
Frederick Holbrook was born on February 15th, 1813.
Frederick Holbrook died on April 28th, 1909 at the age of 96 in Brattleboro (Town in Windham County, Vermont, United States). Today Frederick Holbrook would be 211 years old.
East Windsor (Town of Connecticut, United States).
Brattleboro (Town in Windham County, Vermont, United States).
Frederick Holbrook was born in the zodiac sign Aquarius (The Water-Bearer).
Frederick Holbrook was born in 1813 in the year of the Chinese zodiac Rooster.