Harry Haywood
(1898-1985)

American politician (1898-1985) – Harry Haywood was born in South Omaha (Neighbourhood of Omaha) on February 6th, 1898 and died in New York City (Most populous city in the United States) on January 4th, 1985 at the age of 86. Today Harry Haywood would be 126 years old.

Age

how old was Harry Haywood when he died?

86

Harry Haywood died in 1985 at the age of 86.


Biographical data

Birthday February 6th, 1898 (Sunday)
Place of Birth South Omaha
Neighbourhood of Omaha
Death Date January 4th, 1985 (Friday)
Death place New York City
Most populous city in the United States
Birth sign (Zodiac) Aquarius (The Water-Bearer) ♒
Chinese Zodiac Dog 狗

Other personalities born on February 6

Also born in 1898

Harry Haywood

Birthday

When was Harry Haywood born?

Harry Haywood was born on February 6th, 1898.

Death

When did Harry Haywood die?

Harry Haywood died on January 4th, 1985 at the age of 86 in New York City (Most populous city in the United States). Today Harry Haywood would be 126 years old.

Place of Birth

Where was Harry Haywood born?

South Omaha (Neighbourhood of Omaha).

Death place

Where did Harry Haywood die?

New York City (Most populous city in the United States).

Zodiac

What is the zodiac sign of Harry Haywood?

Harry Haywood was born in the zodiac sign Aquarius (The Water-Bearer).

Chinese Zodiac

Which Chinese zodiac sign does Harry Haywood have?

Harry Haywood was born in 1898 in the year of the Chinese zodiac Dog.

Harry Haywood: Future birthdays

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Died on January 4th, 1985:
Anniversaries of death

American politician (1898-1985)

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