Henri de Ruolz
(1808-1887)

French chemist and composer – Henri de Ruolz was born in Paris (Capital of France) on March 5th, 1808 and died in Paris (Capital of France) on September 30th, 1887 at the age of 79. Today Henri de Ruolz would be 216 years old.

Age

how old was Henri de Ruolz when he died?

79

Henri de Ruolz died in 1887 at the age of 79.


Biographical data

Birthday March 5th, 1808 (Saturday)
Place of Birth Paris
Capital of France
Death Date September 30th, 1887 (Friday)
Death place Paris
Capital of France
Birth sign (Zodiac) Pisces (The Fish) ♓
Chinese Zodiac Dragon 龍

Other personalities born on March 5

Also born in 1808

Henri de Ruolz

Birthday

When was Henri de Ruolz born?

Henri de Ruolz was born on March 5th, 1808.

Death

When did Henri de Ruolz die?

Henri de Ruolz died on September 30th, 1887 at the age of 79 in Paris (Capital of France). Today Henri de Ruolz would be 216 years old.

Place of Birth

Where was Henri de Ruolz born?

Paris (Capital of France).

Death place

Where did Henri de Ruolz die?

Paris (Capital of France).

Zodiac

What is the zodiac sign of Henri de Ruolz?

Henri de Ruolz was born in the zodiac sign Pisces (The Fish).

Chinese Zodiac

Which Chinese zodiac sign does Henri de Ruolz have?

Henri de Ruolz was born in 1808 in the year of the Chinese zodiac Dragon.

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Died on September 30th, 1887:
Anniversaries of death

French chemist and composer

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