Henry Reeve
(1850-1876)

Cuban soldier (1850-1876) – Henry Reeve was born in Brooklyn (Borough of New York City, New York, United States) on April 4th, 1850 and died in Abreus (Municipality of Cuba) on August 4th, 1876 at the age of 26. Today Henry Reeve would be 174 years old.

Age

how old was Henry Reeve when he died?

26

Henry Reeve died in 1876 at the age of 26.


Biographical data

Birthday April 4th, 1850 (Thursday)
Place of Birth Brooklyn
Borough of New York City, New York, United States
Death Date August 4th, 1876 (Friday)
Death place Abreus
Municipality of Cuba
Birth sign (Zodiac) Aries (The Ram) ♈
Chinese Zodiac Dog 狗

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Also born in 1850

Henry Reeve

Birthday

When was Henry Reeve born?

Henry Reeve was born on April 4th, 1850.

Death

When did Henry Reeve die?

Henry Reeve died on August 4th, 1876 at the age of 26 in Abreus (Municipality of Cuba). Today Henry Reeve would be 174 years old.

Place of Birth

Where was Henry Reeve born?

Brooklyn (Borough of New York City, New York, United States).

Death place

Where did Henry Reeve die?

Abreus (Municipality of Cuba).

Zodiac

What is the zodiac sign of Henry Reeve?

Henry Reeve was born in the zodiac sign Aries (The Ram).

Chinese Zodiac

Which Chinese zodiac sign does Henry Reeve have?

Henry Reeve was born in 1850 in the year of the Chinese zodiac Dog.

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Died on August 4th, 1876:
Anniversaries of death

Cuban soldier (1850-1876)

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