James Wyatt
(1746-1813)

English architect; (1746-1813) – James Wyatt was born in Weeford (Village in the United Kingdom) on August 3rd, 1746 and died in Marlborough (Market town and civil parish in the English county of Wiltshire) on September 4th, 1813 at the age of 67. Today James Wyatt would be 277 years old.

Age

how old was James Wyatt when he died?

67

James Wyatt died in 1813 at the age of 67.


Biographical data

Birthday August 3rd, 1746 (Wednesday)
Place of Birth Weeford
Village in the United Kingdom
Death Date September 4th, 1813 (Saturday)
Death place Marlborough
Market town and civil parish in the English county of Wiltshire
Birth sign (Zodiac) Leo (The Lion) ♌
Chinese Zodiac Tiger 兎

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Also born in 1746

James Wyatt

Birthday

When was James Wyatt born?

James Wyatt was born on August 3rd, 1746.

Death

When did James Wyatt die?

James Wyatt died on September 4th, 1813 at the age of 67 in Marlborough (Market town and civil parish in the English county of Wiltshire). Today James Wyatt would be 277 years old.

Place of Birth

Where was James Wyatt born?

Weeford (Village in the United Kingdom).

Death place

Where did James Wyatt die?

Marlborough (Market town and civil parish in the English county of Wiltshire).

Zodiac

What is the zodiac sign of James Wyatt?

James Wyatt was born in the zodiac sign Leo (The Lion).

Chinese Zodiac

Which Chinese zodiac sign does James Wyatt have?

James Wyatt was born in 1746 in the year of the Chinese zodiac Tiger.

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Died on September 4th, 1813:
Anniversaries of death

English architect; (1746-1813)

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