Javier de Burgos
(1778-1848)

Spanish writer, politician and jurist (1778-1848) – Javier de Burgos was born in Motril (Town and municipality in Granada, Spain) on October 22nd, 1778 and died in Madrid (Municipality and capital of Spain) on January 22nd, 1848 at the age of 69. Today Javier de Burgos would be 245 years old.

Age

how old was Javier de Burgos when he died?

69

Javier de Burgos died in 1848 at the age of 69.


Biographical data

Birthday October 22nd, 1778 (Thursday)
Place of Birth Motril
Town and municipality in Granada, Spain
Death Date January 22nd, 1848 (Saturday)
Death place Madrid
Municipality and capital of Spain
Birth sign (Zodiac) Libra (The Scales) ♎
Chinese Zodiac Dog 狗

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Javier de Burgos

Birthday

When was Javier de Burgos born?

Javier de Burgos was born on October 22nd, 1778.

Death

When did Javier de Burgos die?

Javier de Burgos died on January 22nd, 1848 at the age of 69 in Madrid (Municipality and capital of Spain). Today Javier de Burgos would be 245 years old.

Place of Birth

Where was Javier de Burgos born?

Motril (Town and municipality in Granada, Spain).

Death place

Where did Javier de Burgos die?

Madrid (Municipality and capital of Spain).

Zodiac

What is the zodiac sign of Javier de Burgos?

Javier de Burgos was born in the zodiac sign Libra (The Scales).

Chinese Zodiac

Which Chinese zodiac sign does Javier de Burgos have?

Javier de Burgos was born in 1778 in the year of the Chinese zodiac Dog.

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Died on January 22nd, 1848:
Anniversaries of death

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Spanish writer, politician and jurist (1778-1848)