Joachim Rosenow
(1618-1701)

JoachimRosenow
JoachimRosenow Ölgemälde von Joachim Rosenow Foto: Unknown authorUnknown author / Public Domain

German mathematician – Joachim Rosenow was born in Anklam (Town in Germany) on November 5th, 1618 and died in on June 20th, 1701 at the age of 82. Today Joachim Rosenow would be 405 years old.

Age

how old was Joachim Rosenow when he died?

82

Joachim Rosenow died in 1701 at the age of 82.


Biographical data

Birthday November 5th, 1618 (Monday)
Place of Birth Anklam
Town in Germany
Death Date June 20th, 1701 (Monday)
Birth sign (Zodiac) Scorpio (The Scorpion) ♏
Chinese Zodiac Horse 馬

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Joachim Rosenow

Birthday

When was Joachim Rosenow born?

Joachim Rosenow was born on November 5th, 1618.

Death

When did Joachim Rosenow die?

Joachim Rosenow died on June 20th, 1701 at the age of 82 in . Today Joachim Rosenow would be 405 years old.

Place of Birth

Where was Joachim Rosenow born?

Anklam (Town in Germany).

Zodiac

What is the zodiac sign of Joachim Rosenow?

Joachim Rosenow was born in the zodiac sign Scorpio (The Scorpion).

Chinese Zodiac

Which Chinese zodiac sign does Joachim Rosenow have?

Joachim Rosenow was born in 1618 in the year of the Chinese zodiac Horse.

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Died on June 20th, 1701:
Anniversaries of death

German mathematician

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