American merchant, slave trader, and statesman from Providence, Rhode Island (1736-1803) – John Brown was born in Providence (Capital city of Rhode Island, United States) on January 27th, 1736 and died in Providence (Capital city of Rhode Island, United States) on September 20th, 1803 at the age of 67. Today John Brown would be 288 years old.
John Brown died in 1803 at the age of 67.
Birthday | January 27th, 1736 (Friday) |
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Place of Birth | Providence Capital city of Rhode Island, United States |
Death Date | September 20th, 1803 (Tuesday) |
Death place | Providence Capital city of Rhode Island, United States |
Birth sign (Zodiac) | Aquarius (The Water-Bearer) ♒ |
Chinese Zodiac | Dragon 龍 |
John Brown was born on January 27th, 1736.
John Brown died on September 20th, 1803 at the age of 67 in Providence (Capital city of Rhode Island, United States). Today John Brown would be 288 years old.
Providence (Capital city of Rhode Island, United States).
Providence (Capital city of Rhode Island, United States).
John Brown was born in the zodiac sign Aquarius (The Water-Bearer).
John Brown was born in 1736 in the year of the Chinese zodiac Dragon.