John Calhoun Sheppard
(1850-1931)

American politician – John Calhoun Sheppard was born in Edgefield County (County in South Carolina, United States) on July 5th, 1850 and died in on October 7th, 1931 at the age of 81. Today John Calhoun Sheppard would be 174 years old.

Age

how old was John Calhoun Sheppard when he died?

81

John Calhoun Sheppard died in 1931 at the age of 81.


Biographical data

Birthday July 5th, 1850 (Friday)
Place of Birth Edgefield County
County in South Carolina, United States
Death Date October 7th, 1931 (Wednesday)
Birth sign (Zodiac) Cancer (The Crab) ♋
Chinese Zodiac Dog 狗

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Also born in 1850

John Calhoun Sheppard

Birthday

When was John Calhoun Sheppard born?

John Calhoun Sheppard was born on July 5th, 1850.

Death

When did John Calhoun Sheppard die?

John Calhoun Sheppard died on October 7th, 1931 at the age of 81 in . Today John Calhoun Sheppard would be 174 years old.

Place of Birth

Where was John Calhoun Sheppard born?

Edgefield County (County in South Carolina, United States).

Zodiac

What is the zodiac sign of John Calhoun Sheppard?

John Calhoun Sheppard was born in the zodiac sign Cancer (The Crab).

Chinese Zodiac

Which Chinese zodiac sign does John Calhoun Sheppard have?

John Calhoun Sheppard was born in 1850 in the year of the Chinese zodiac Dog.

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Died on October 7th, 1931:
Anniversaries of death

American politician

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