John Elliott
(1773-1827)

American politician (1773-1827) – John Elliott was born in Liberty County (County in Georgia, United States) on October 24th, 1773 and died in Liberty County (County in Georgia, United States) on August 9th, 1827 at the age of 53. Today John Elliott would be 250 years old.

Age

how old was John Elliott when he died?

53

John Elliott died in 1827 at the age of 53.


Biographical data

Birthday October 24th, 1773 (Sunday)
Place of Birth Liberty County
County in Georgia, United States
Death Date August 9th, 1827 (Thursday)
Death place Liberty County
County in Georgia, United States
Birth sign (Zodiac) Scorpio (The Scorpion) ♏
Chinese Zodiac Snake 蛇

Other personalities born on October 24

Also born in 1773

John Elliott

Birthday

When was John Elliott born?

John Elliott was born on October 24th, 1773.

Death

When did John Elliott die?

John Elliott died on August 9th, 1827 at the age of 53 in Liberty County (County in Georgia, United States). Today John Elliott would be 250 years old.

Place of Birth

Where was John Elliott born?

Liberty County (County in Georgia, United States).

Death place

Where did John Elliott die?

Liberty County (County in Georgia, United States).

Zodiac

What is the zodiac sign of John Elliott?

John Elliott was born in the zodiac sign Scorpio (The Scorpion).

Chinese Zodiac

Which Chinese zodiac sign does John Elliott have?

John Elliott was born in 1773 in the year of the Chinese zodiac Snake.

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Died on August 9th, 1827:
Anniversaries of death

American politician (1773-1827)

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