John Wesley Hardin
(1853-1895)

American Old West character – John Wesley Hardin was born in Bonham (City in Texas, USA) on May 26th, 1853 and died in El Paso (City in and county seat of El Paso County, Texas, United States) on August 19th, 1895 at the age of 42. Today John Wesley Hardin would be 170 years old.

Age

how old was John Wesley Hardin when he died?

42

John Wesley Hardin died in 1895 at the age of 42.


Biographical data

Birthday May 26th, 1853 (Thursday)
Place of Birth Bonham
City in Texas, USA
Death Date August 19th, 1895 (Monday)
Death place El Paso
City in and county seat of El Paso County, Texas, United States
Birth sign (Zodiac) Gemini (The Twins) ♊
Chinese Zodiac Ox 牛

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Also born in 1853

John Wesley Hardin

Birthday

When was John Wesley Hardin born?

John Wesley Hardin was born on May 26th, 1853.

Death

When did John Wesley Hardin die?

John Wesley Hardin died on August 19th, 1895 at the age of 42 in El Paso (City in and county seat of El Paso County, Texas, United States). Today John Wesley Hardin would be 170 years old.

Place of Birth

Where was John Wesley Hardin born?

Bonham (City in Texas, USA).

Death place

Where did John Wesley Hardin die?

El Paso (City in and county seat of El Paso County, Texas, United States).

Zodiac

What is the zodiac sign of John Wesley Hardin?

John Wesley Hardin was born in the zodiac sign Gemini (The Twins).

Chinese Zodiac

Which Chinese zodiac sign does John Wesley Hardin have?

John Wesley Hardin was born in 1853 in the year of the Chinese zodiac Ox.

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Died on August 19th, 1895:
Anniversaries of death

American Old West character

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