Lee Wulff
(1905-1991)

American fisherman – Lee Wulff was born in Valdez (City in Alaska, United States) on February 10th, 1905 and died in Hancock (Town in Delaware County, New York, United States) on April 28th, 1991 at the age of 86. Today Lee Wulff would be 119 years old.

Age

how old was Lee Wulff when he died?

86

Lee Wulff died in 1991 at the age of 86.


Biographical data

Birthday February 10th, 1905 (Friday)
Place of Birth Valdez
City in Alaska, United States
Death Date April 28th, 1991 (Sunday)
Death place Hancock
Town in Delaware County, New York, United States
Birth sign (Zodiac) Aquarius (The Water-Bearer) ♒
Chinese Zodiac Snake 蛇

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Lee Wulff

Birthday

When was Lee Wulff born?

Lee Wulff was born on February 10th, 1905.

Death

When did Lee Wulff die?

Lee Wulff died on April 28th, 1991 at the age of 86 in Hancock (Town in Delaware County, New York, United States). Today Lee Wulff would be 119 years old.

Place of Birth

Where was Lee Wulff born?

Valdez (City in Alaska, United States).

Death place

Where did Lee Wulff die?

Hancock (Town in Delaware County, New York, United States).

Zodiac

What is the zodiac sign of Lee Wulff?

Lee Wulff was born in the zodiac sign Aquarius (The Water-Bearer).

Chinese Zodiac

Which Chinese zodiac sign does Lee Wulff have?

Lee Wulff was born in 1905 in the year of the Chinese zodiac Snake.

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Died on April 28th, 1991:
Anniversaries of death

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