Robert E. Howard
(1906-1936)

American author (1906-1936) – Robert E. Howard was born in Peaster (Town in Texas, United States) on January 22nd, 1906 and died in Cross Plains (Town in Texas, United States) on June 11th, 1936 at the age of 30. Today Robert E. Howard would be 118 years old.

Age

how old was Robert E. Howard when he died?

30

Robert E. Howard died in 1936 at the age of 30.


Biographical data

Birthday January 22nd, 1906 (Monday)
Place of Birth Peaster
Town in Texas, United States
Death Date June 11th, 1936 (Thursday)
Death place Cross Plains
Town in Texas, United States
Birth sign (Zodiac) Aquarius (The Water-Bearer) ♒
Chinese Zodiac Horse 馬

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Also born in 1906

Robert E. Howard

Birthday

When was Robert E. Howard born?

Robert E. Howard was born on January 22nd, 1906.

Death

When did Robert E. Howard die?

Robert E. Howard died on June 11th, 1936 at the age of 30 in Cross Plains (Town in Texas, United States). Today Robert E. Howard would be 118 years old.

Place of Birth

Where was Robert E. Howard born?

Peaster (Town in Texas, United States).

Death place

Where did Robert E. Howard die?

Cross Plains (Town in Texas, United States).

Zodiac

What is the zodiac sign of Robert E. Howard?

Robert E. Howard was born in the zodiac sign Aquarius (The Water-Bearer).

Chinese Zodiac

Which Chinese zodiac sign does Robert E. Howard have?

Robert E. Howard was born in 1906 in the year of the Chinese zodiac Horse.

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Died on June 11th, 1936:
Anniversaries of death

American author (1906-1936)

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