S. Z. Sakall
(1883-1955)

Hungarian actor – S. Z. Sakall was born in Budapest (Capital and largest city of Hungary) on February 2nd, 1883 and died in Hollywood (Neighborhood in Los Angeles, California, United States) on February 12th, 1955 at the age of 72. Today S. Z. Sakall would be 141 years old.

Age

how old was S. Z. Sakall when he died?

72

S. Z. Sakall died in 1955 at the age of 72.


Biographical data

Birthday February 2nd, 1883 (Friday)
Place of Birth Budapest
Capital and largest city of Hungary
Death Date February 12th, 1955 (Saturday)
Death place Hollywood
Neighborhood in Los Angeles, California, United States
Birth sign (Zodiac) Aquarius (The Water-Bearer) ♒
Chinese Zodiac Goat 羊

Other personalities born on February 2

Also born in 1883

S. Z. Sakall

Birthday

When was S. Z. Sakall born?

S. Z. Sakall was born on February 2nd, 1883.

Death

When did S. Z. Sakall die?

S. Z. Sakall died on February 12th, 1955 at the age of 72 in Hollywood (Neighborhood in Los Angeles, California, United States). Today S. Z. Sakall would be 141 years old.

Place of Birth

Where was S. Z. Sakall born?

Budapest (Capital and largest city of Hungary).

Death place

Where did S. Z. Sakall die?

Hollywood (Neighborhood in Los Angeles, California, United States).

Zodiac

What is the zodiac sign of S. Z. Sakall?

S. Z. Sakall was born in the zodiac sign Aquarius (The Water-Bearer).

Chinese Zodiac

Which Chinese zodiac sign does S. Z. Sakall have?

S. Z. Sakall was born in 1883 in the year of the Chinese zodiac Goat.

S. Z. Sakall: Future birthdays

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Died on February 12th, 1955:
Anniversaries of death

Hungarian actor

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