Seth Bullock
(1849-1919)

Lawman (1849-1919) – Seth Bullock was born in Amherstburg (Town in Essex County, Ontario, Canada) on July 23rd, 1849 and died in Deadwood (City in and county seat of Lawrence County, South Dakota, United States) on September 23rd, 1919 at the age of 70. Today Seth Bullock would be 174 years old.

Age

how old was Seth Bullock when he died?

70

Seth Bullock died in 1919 at the age of 70.


Biographical data

Birthday July 23rd, 1849 (Monday)
Place of Birth Amherstburg
Town in Essex County, Ontario, Canada
Death Date September 23rd, 1919 (Tuesday)
Death place Deadwood
City in and county seat of Lawrence County, South Dakota, United States
Birth sign (Zodiac) Leo (The Lion) ♌
Chinese Zodiac Rooster 雞

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Also born in 1849

Seth Bullock

Birthday

When was Seth Bullock born?

Seth Bullock was born on July 23rd, 1849.

Death

When did Seth Bullock die?

Seth Bullock died on September 23rd, 1919 at the age of 70 in Deadwood (City in and county seat of Lawrence County, South Dakota, United States). Today Seth Bullock would be 174 years old.

Place of Birth

Where was Seth Bullock born?

Amherstburg (Town in Essex County, Ontario, Canada).

Death place

Where did Seth Bullock die?

Deadwood (City in and county seat of Lawrence County, South Dakota, United States).

Zodiac

What is the zodiac sign of Seth Bullock?

Seth Bullock was born in the zodiac sign Leo (The Lion).

Chinese Zodiac

Which Chinese zodiac sign does Seth Bullock have?

Seth Bullock was born in 1849 in the year of the Chinese zodiac Rooster.

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Died on September 23rd, 1919:
Anniversaries of death

Lawman (1849-1919)

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