Théodore Ballu
(1817-1885)

French architect (1817-1885) – Théodore Ballu was born in Paris (Capital of France) on June 8th, 1817 and died in Paris (Capital of France) on May 22nd, 1885 at the age of 67. Today Théodore Ballu would be 206 years old.

Age

how old was Théodore Ballu when he died?

67

Théodore Ballu died in 1885 at the age of 67.


Biographical data

Birthday June 8th, 1817 (Sunday)
Place of Birth Paris
Capital of France
Death Date May 22nd, 1885 (Friday)
Death place Paris
Capital of France
Birth sign (Zodiac) Gemini (The Twins) ♊
Chinese Zodiac Ox 牛

Other personalities born on June 8

Also born in 1817

Théodore Ballu

Birthday

When was Théodore Ballu born?

Théodore Ballu was born on June 8th, 1817.

Death

When did Théodore Ballu die?

Théodore Ballu died on May 22nd, 1885 at the age of 67 in Paris (Capital of France). Today Théodore Ballu would be 206 years old.

Place of Birth

Where was Théodore Ballu born?

Paris (Capital of France).

Death place

Where did Théodore Ballu die?

Paris (Capital of France).

Zodiac

What is the zodiac sign of Théodore Ballu?

Théodore Ballu was born in the zodiac sign Gemini (The Twins).

Chinese Zodiac

Which Chinese zodiac sign does Théodore Ballu have?

Théodore Ballu was born in 1817 in the year of the Chinese zodiac Ox.

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Died on May 22nd, 1885:
Anniversaries of death

French architect (1817-1885)

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