Théodore Chassériau
(1819-1856)

French romantic painter (1819-1856) – Théodore Chassériau was born in El Limón (Municipality district in the Dominican Republic) on September 20th, 1819 and died in Paris (Capital of France) on October 8th, 1856 at the age of 37. Today Théodore Chassériau would be 204 years old.

Age

how old was Théodore Chassériau when he died?

37

Théodore Chassériau died in 1856 at the age of 37.


Biographical data

Birthday September 20th, 1819 (Monday)
Place of Birth El Limón
Municipality district in the Dominican Republic
Death Date October 8th, 1856 (Wednesday)
Death place Paris
Capital of France
Birth sign (Zodiac) Virgo (The Maiden) ♍
Chinese Zodiac Rabbit 兔

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Also born in 1819

Théodore Chassériau

Birthday

When was Théodore Chassériau born?

Théodore Chassériau was born on September 20th, 1819.

Death

When did Théodore Chassériau die?

Théodore Chassériau died on October 8th, 1856 at the age of 37 in Paris (Capital of France). Today Théodore Chassériau would be 204 years old.

Place of Birth

Where was Théodore Chassériau born?

El Limón (Municipality district in the Dominican Republic).

Death place

Where did Théodore Chassériau die?

Paris (Capital of France).

Zodiac

What is the zodiac sign of Théodore Chassériau?

Théodore Chassériau was born in the zodiac sign Virgo (The Maiden).

Chinese Zodiac

Which Chinese zodiac sign does Théodore Chassériau have?

Théodore Chassériau was born in 1819 in the year of the Chinese zodiac Rabbit.

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Died on October 8th, 1856:
Anniversaries of death

French romantic painter (1819-1856)

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