Théodore Rousseau
(1812-1867)

French painter (1812-1867) – Théodore Rousseau was born in Paris (Capital of France) on April 15th, 1812 and died in Barbizon (Commune in Seine-et-Marne, France) on December 22nd, 1867 at the age of 55. Today Théodore Rousseau would be 212 years old.

Age

how old was Théodore Rousseau when he died?

55

Théodore Rousseau died in 1867 at the age of 55.


Biographical data

Birthday April 15th, 1812 (Wednesday)
Place of Birth Paris
Capital of France
Death Date December 22nd, 1867 (Sunday)
Death place Barbizon
Commune in Seine-et-Marne, France
Birth sign (Zodiac) Aries (The Ram) ♈
Chinese Zodiac Monkey 猴

Other personalities born on April 15

Also born in 1812

Théodore Rousseau

Birthday

When was Théodore Rousseau born?

Théodore Rousseau was born on April 15th, 1812.

Death

When did Théodore Rousseau die?

Théodore Rousseau died on December 22nd, 1867 at the age of 55 in Barbizon (Commune in Seine-et-Marne, France). Today Théodore Rousseau would be 212 years old.

Place of Birth

Where was Théodore Rousseau born?

Paris (Capital of France).

Death place

Where did Théodore Rousseau die?

Barbizon (Commune in Seine-et-Marne, France).

Zodiac

What is the zodiac sign of Théodore Rousseau?

Théodore Rousseau was born in the zodiac sign Aries (The Ram).

Chinese Zodiac

Which Chinese zodiac sign does Théodore Rousseau have?

Théodore Rousseau was born in 1812 in the year of the Chinese zodiac Monkey.

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Died on December 22nd, 1867:
Anniversaries of death

French painter (1812-1867)

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