Waldo Semon
(1898-1999)

American inventor – Waldo Semon was born in Demopolis (City in Alabama, United States) on September 10th, 1898 and died in Hudson (City in Ohio) on May 26th, 1999 at the age of 100. Today Waldo Semon would be 125 years old.

Age

how old was Waldo Semon when he died?

100

Waldo Semon died in 1999 at the age of 100.


Biographical data

Birthday September 10th, 1898 (Saturday)
Place of Birth Demopolis
City in Alabama, United States
Death Date May 26th, 1999 (Wednesday)
Death place Hudson
City in Ohio
Birth sign (Zodiac) Virgo (The Maiden) ♍
Chinese Zodiac Dog 狗

Other personalities born on September 10

Also born in 1898

Waldo Semon

Birthday

When was Waldo Semon born?

Waldo Semon was born on September 10th, 1898.

Death

When did Waldo Semon die?

Waldo Semon died on May 26th, 1999 at the age of 100 in Hudson (City in Ohio). Today Waldo Semon would be 125 years old.

Place of Birth

Where was Waldo Semon born?

Demopolis (City in Alabama, United States).

Death place

Where did Waldo Semon die?

Hudson (City in Ohio).

Zodiac

What is the zodiac sign of Waldo Semon?

Waldo Semon was born in the zodiac sign Virgo (The Maiden).

Chinese Zodiac

Which Chinese zodiac sign does Waldo Semon have?

Waldo Semon was born in 1898 in the year of the Chinese zodiac Dog.

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Died on May 26th, 1999:
Anniversaries of death

American inventor

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