William Hoyt
(1875-1954)

American pole vaulter – William Hoyt was born in Glastonbury (Town in Hartford County, Connecticut, USA) on May 7th, 1875 and died in New York (State of the United States of America) on December 1st, 1954 at the age of 79. Today William Hoyt would be 148 years old.

Age

how old was William Hoyt when he died?

79

William Hoyt died in 1954 at the age of 79.


Biographical data

Birthday May 7th, 1875 (Friday)
Place of Birth Glastonbury
Town in Hartford County, Connecticut, USA
Death Date December 1st, 1954 (Wednesday)
Death place New York
State of the United States of America
Birth sign (Zodiac) Taurus (The Bull) ♉
Chinese Zodiac Pig 豬

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William Hoyt

Birthday

When was William Hoyt born?

William Hoyt was born on May 7th, 1875.

Death

When did William Hoyt die?

William Hoyt died on December 1st, 1954 at the age of 79 in New York (State of the United States of America). Today William Hoyt would be 148 years old.

Place of Birth

Where was William Hoyt born?

Glastonbury (Town in Hartford County, Connecticut, USA).

Death place

Where did William Hoyt die?

New York (State of the United States of America).

Zodiac

What is the zodiac sign of William Hoyt?

William Hoyt was born in the zodiac sign Taurus (The Bull).

Chinese Zodiac

Which Chinese zodiac sign does William Hoyt have?

William Hoyt was born in 1875 in the year of the Chinese zodiac Pig.

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Died on December 1st, 1954:
Anniversaries of death

American pole vaulter

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