A. C. Gibbs
(1825-1886)

American politician (1825-1886) – A. C. Gibbs was born in Cattaraugus County (County in New York, United States) on July 9th, 1825 and died in London (Capital and largest city of England and the United Kingdom) on December 29th, 1886 at the age of 61. Today A. C. Gibbs would be 198 years old.

Age

how old was A. C. Gibbs when he died?

61

A. C. Gibbs died in 1886 at the age of 61.


Biographical data

Birthday July 9th, 1825 (Saturday)
Place of Birth Cattaraugus County
County in New York, United States
Death Date December 29th, 1886 (Wednesday)
Death place London
Capital and largest city of England and the United Kingdom
Birth sign (Zodiac) Cancer (The Crab) ♋
Chinese Zodiac Rooster 雞

Other personalities born on July 9

Also born in 1825

A. C. Gibbs

Birthday

When was A. C. Gibbs born?

A. C. Gibbs was born on July 9th, 1825.

Death

When did A. C. Gibbs die?

A. C. Gibbs died on December 29th, 1886 at the age of 61 in London (Capital and largest city of England and the United Kingdom). Today A. C. Gibbs would be 198 years old.

Place of Birth

Where was A. C. Gibbs born?

Cattaraugus County (County in New York, United States).

Death place

Where did A. C. Gibbs die?

London (Capital and largest city of England and the United Kingdom).

Zodiac

What is the zodiac sign of A. C. Gibbs?

A. C. Gibbs was born in the zodiac sign Cancer (The Crab).

Chinese Zodiac

Which Chinese zodiac sign does A. C. Gibbs have?

A. C. Gibbs was born in 1825 in the year of the Chinese zodiac Rooster.

A. C. Gibbs: Future birthdays

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Died on December 29th, 1886:
Anniversaries of death

American politician (1825-1886)

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