Abraham Jacobi
(1830-1919)

German-American pediatrician (1830-1919) – Abraham Jacobi was born in Hartum (Human settlement in Germany) on May 6th, 1830 and died in Lake George (Lake in Warren County, New York, USA) on July 10th, 1919 at the age of 89. Today Abraham Jacobi would be 193 years old.

Age

how old was Abraham Jacobi when he died?

89

Abraham Jacobi died in 1919 at the age of 89.


Biographical data

Birthday May 6th, 1830 (Thursday)
Place of Birth Hartum
Human settlement in Germany
Death Date July 10th, 1919 (Thursday)
Death place Lake George
Lake in Warren County, New York, USA
Birth sign (Zodiac) Taurus (The Bull) ♉
Chinese Zodiac Tiger 兎

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Abraham Jacobi

Birthday

When was Abraham Jacobi born?

Abraham Jacobi was born on May 6th, 1830.

Death

When did Abraham Jacobi die?

Abraham Jacobi died on July 10th, 1919 at the age of 89 in Lake George (Lake in Warren County, New York, USA). Today Abraham Jacobi would be 193 years old.

Place of Birth

Where was Abraham Jacobi born?

Hartum (Human settlement in Germany).

Death place

Where did Abraham Jacobi die?

Lake George (Lake in Warren County, New York, USA).

Zodiac

What is the zodiac sign of Abraham Jacobi?

Abraham Jacobi was born in the zodiac sign Taurus (The Bull).

Chinese Zodiac

Which Chinese zodiac sign does Abraham Jacobi have?

Abraham Jacobi was born in 1830 in the year of the Chinese zodiac Tiger.

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Died on July 10th, 1919:
Anniversaries of death

German-American pediatrician (1830-1919)

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