Agathe de Rambaud
(1764-1853)

French royal nurse (1764-1853) – Agathe de Rambaud was born in Versailles (French commune in Yvelines, Île-de-France) on December 10th, 1764 and died in Aramon (Commune in Gard, France) on October 19th, 1853 at the age of 88. Today Agathe de Rambaud would be 259 years old.

Age

how old was Agathe de Rambaud when he died?

88

Agathe de Rambaud died in 1853 at the age of 88.


Biographical data

Birthday December 10th, 1764 (Monday)
Place of Birth Versailles
French commune in Yvelines, Île-de-France
Death Date October 19th, 1853 (Wednesday)
Death place Aramon
Commune in Gard, France
Birth sign (Zodiac) Sagittarius (The Centaur/Archer) ♐
Chinese Zodiac Monkey 猴

Other personalities born on December 10

Also born in 1764

Agathe de Rambaud

Birthday

When was Agathe de Rambaud born?

Agathe de Rambaud was born on December 10th, 1764.

Death

When did Agathe de Rambaud die?

Agathe de Rambaud died on October 19th, 1853 at the age of 88 in Aramon (Commune in Gard, France). Today Agathe de Rambaud would be 259 years old.

Place of Birth

Where was Agathe de Rambaud born?

Versailles (French commune in Yvelines, Île-de-France).

Death place

Where did Agathe de Rambaud die?

Aramon (Commune in Gard, France).

Zodiac

What is the zodiac sign of Agathe de Rambaud?

Agathe de Rambaud was born in the zodiac sign Sagittarius (The Centaur/Archer).

Chinese Zodiac

Which Chinese zodiac sign does Agathe de Rambaud have?

Agathe de Rambaud was born in 1764 in the year of the Chinese zodiac Monkey.

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Died on October 19th, 1853:
Anniversaries of death

French royal nurse (1764-1853)

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