American artist (1867-1959) – Alexander Rummler was born in Dubuque (City in and county seat of Dubuque, Iowa, United States) on July 25th, 1867 and died in Stamford (City in Fairfield County, Connecticut, United States) on November 30th, 1958 at the age of 91. Today Alexander Rummler would be 156 years old.
Alexander Rummler died in 1958 at the age of 91.
Birthday | July 25th, 1867 (Thursday) |
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Place of Birth | Dubuque City in and county seat of Dubuque, Iowa, United States |
Death Date | November 30th, 1958 (Sunday) |
Death place | Stamford City in Fairfield County, Connecticut, United States |
Birth sign (Zodiac) | Leo (The Lion) ♌ |
Chinese Zodiac | Rabbit 兔 |
Alexander Rummler was born on July 25th, 1867.
Alexander Rummler died on November 30th, 1958 at the age of 91 in Stamford (City in Fairfield County, Connecticut, United States). Today Alexander Rummler would be 156 years old.
Dubuque (City in and county seat of Dubuque, Iowa, United States).
Stamford (City in Fairfield County, Connecticut, United States).
Alexander Rummler was born in the zodiac sign Leo (The Lion).
Alexander Rummler was born in 1867 in the year of the Chinese zodiac Rabbit.