Alfred Arndt
(1898-1976)

German architect – Alfred Arndt was born in Elbląg (Place in Warmian-Masurian, Poland) on November 26th, 1898 and died in Darmstadt (City in Hesse, Germany) on October 7th, 1976 at the age of 77. Today Alfred Arndt would be 125 years old.

Age

how old was Alfred Arndt when he died?

77

Alfred Arndt died in 1976 at the age of 77.


Biographical data

Birthday November 26th, 1898 (Saturday)
Place of Birth Elbląg
Place in Warmian-Masurian, Poland
Death Date October 7th, 1976 (Thursday)
Death place Darmstadt
City in Hesse, Germany
Birth sign (Zodiac) Sagittarius (The Centaur/Archer) ♐
Chinese Zodiac Dog 狗

Other personalities born on November 26

Also born in 1898

Alfred Arndt

Birthday

When was Alfred Arndt born?

Alfred Arndt was born on November 26th, 1898.

Death

When did Alfred Arndt die?

Alfred Arndt died on October 7th, 1976 at the age of 77 in Darmstadt (City in Hesse, Germany). Today Alfred Arndt would be 125 years old.

Place of Birth

Where was Alfred Arndt born?

Elbląg (Place in Warmian-Masurian, Poland).

Death place

Where did Alfred Arndt die?

Darmstadt (City in Hesse, Germany).

Zodiac

What is the zodiac sign of Alfred Arndt?

Alfred Arndt was born in the zodiac sign Sagittarius (The Centaur/Archer).

Chinese Zodiac

Which Chinese zodiac sign does Alfred Arndt have?

Alfred Arndt was born in 1898 in the year of the Chinese zodiac Dog.

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Died on October 7th, 1976:
Anniversaries of death

German architect

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