Alfred Austin
(1835-1913)

British writer and poet – Alfred Austin was born in Leeds (City in West Yorkshire, England, United Kingdom) on May 30th, 1835 and died in Ashford (Town in the borough of Ashford in Kent, England) on June 2nd, 1913 at the age of 78. Today Alfred Austin would be 188 years old.

Age

how old was Alfred Austin when he died?

78

Alfred Austin died in 1913 at the age of 78.


Biographical data

Birthday May 30th, 1835 (Saturday)
Place of Birth Leeds
City in West Yorkshire, England, United Kingdom
Death Date June 2nd, 1913 (Monday)
Death place Ashford
Town in the borough of Ashford in Kent, England
Birth sign (Zodiac) Gemini (The Twins) ♊
Chinese Zodiac Goat 羊

Other personalities born on May 30

Also born in 1835

Alfred Austin

Birthday

When was Alfred Austin born?

Alfred Austin was born on May 30th, 1835.

Death

When did Alfred Austin die?

Alfred Austin died on June 2nd, 1913 at the age of 78 in Ashford (Town in the borough of Ashford in Kent, England). Today Alfred Austin would be 188 years old.

Place of Birth

Where was Alfred Austin born?

Leeds (City in West Yorkshire, England, United Kingdom).

Death place

Where did Alfred Austin die?

Ashford (Town in the borough of Ashford in Kent, England).

Zodiac

What is the zodiac sign of Alfred Austin?

Alfred Austin was born in the zodiac sign Gemini (The Twins).

Chinese Zodiac

Which Chinese zodiac sign does Alfred Austin have?

Alfred Austin was born in 1835 in the year of the Chinese zodiac Goat.

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Died on June 2nd, 1913:
Anniversaries of death

British writer and poet

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