Alfred de Bougy
(1814-1871)

French poet (1814-1871) – Alfred de Bougy was born in Grenoble (Commune in Isère, France) on November 5th, 1814 and died in Thonon-les-Bains (Commune in Haute-Savoie, France) on September 4th, 1871 at the age of 56. Today Alfred de Bougy would be 209 years old.

Age

how old was Alfred de Bougy when he died?

56

Alfred de Bougy died in 1871 at the age of 56.


Biographical data

Birthday November 5th, 1814 (Saturday)
Place of Birth Grenoble
Commune in Isère, France
Death Date September 4th, 1871 (Monday)
Death place Thonon-les-Bains
Commune in Haute-Savoie, France
Birth sign (Zodiac) Scorpio (The Scorpion) ♏
Chinese Zodiac Dog 狗

Other personalities born on November 5

Also born in 1814

Alfred de Bougy

Birthday

When was Alfred de Bougy born?

Alfred de Bougy was born on November 5th, 1814.

Death

When did Alfred de Bougy die?

Alfred de Bougy died on September 4th, 1871 at the age of 56 in Thonon-les-Bains (Commune in Haute-Savoie, France). Today Alfred de Bougy would be 209 years old.

Place of Birth

Where was Alfred de Bougy born?

Grenoble (Commune in Isère, France).

Death place

Where did Alfred de Bougy die?

Thonon-les-Bains (Commune in Haute-Savoie, France).

Zodiac

What is the zodiac sign of Alfred de Bougy?

Alfred de Bougy was born in the zodiac sign Scorpio (The Scorpion).

Chinese Zodiac

Which Chinese zodiac sign does Alfred de Bougy have?

Alfred de Bougy was born in 1814 in the year of the Chinese zodiac Dog.

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Died on September 4th, 1871:
Anniversaries of death

French poet (1814-1871)

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