Alfred Vail
(1809-1859)

American inventor (1809-1859) – Alfred Vail was born in Morristown (Town in Morris County, New Jersey, United States) on September 25th, 1809 and died in Morristown (Town in Morris County, New Jersey, United States) on January 18th, 1859 at the age of 49. Today Alfred Vail would be 214 years old.

Age

how old was Alfred Vail when he died?

49

Alfred Vail died in 1859 at the age of 49.


Biographical data

Birthday September 25th, 1809 (Monday)
Place of Birth Morristown
Town in Morris County, New Jersey, United States
Death Date January 18th, 1859 (Tuesday)
Death place Morristown
Town in Morris County, New Jersey, United States
Birth sign (Zodiac) Libra (The Scales) ♎
Chinese Zodiac Snake 蛇

Other personalities born on September 25

Also born in 1809

Alfred Vail

Birthday

When was Alfred Vail born?

Alfred Vail was born on September 25th, 1809.

Death

When did Alfred Vail die?

Alfred Vail died on January 18th, 1859 at the age of 49 in Morristown (Town in Morris County, New Jersey, United States). Today Alfred Vail would be 214 years old.

Place of Birth

Where was Alfred Vail born?

Morristown (Town in Morris County, New Jersey, United States).

Death place

Where did Alfred Vail die?

Morristown (Town in Morris County, New Jersey, United States).

Zodiac

What is the zodiac sign of Alfred Vail?

Alfred Vail was born in the zodiac sign Libra (The Scales).

Chinese Zodiac

Which Chinese zodiac sign does Alfred Vail have?

Alfred Vail was born in 1809 in the year of the Chinese zodiac Snake.

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Died on January 18th, 1859:
Anniversaries of death

American inventor (1809-1859)

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