Alfredo de Oro
(1863-1948)

Cuban pool player (1863–1948) – Alfredo de Oro was born in Manzanillo (City in Cuba) on April 28th, 1863 and died in on June 2nd, 1948 at the age of 85. Today Alfredo de Oro would be 161 years old.

Age

how old was Alfredo de Oro when he died?

85

Alfredo de Oro died in 1948 at the age of 85.


Biographical data

Birthday April 28th, 1863 (Tuesday)
Place of Birth Manzanillo
City in Cuba
Death Date June 2nd, 1948 (Wednesday)
Birth sign (Zodiac) Taurus (The Bull) ♉
Chinese Zodiac Pig 豬

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Alfredo de Oro

Birthday

When was Alfredo de Oro born?

Alfredo de Oro was born on April 28th, 1863.

Death

When did Alfredo de Oro die?

Alfredo de Oro died on June 2nd, 1948 at the age of 85 in . Today Alfredo de Oro would be 161 years old.

Place of Birth

Where was Alfredo de Oro born?

Manzanillo (City in Cuba).

Zodiac

What is the zodiac sign of Alfredo de Oro?

Alfredo de Oro was born in the zodiac sign Taurus (The Bull).

Chinese Zodiac

Which Chinese zodiac sign does Alfredo de Oro have?

Alfredo de Oro was born in 1863 in the year of the Chinese zodiac Pig.

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Died on June 2nd, 1948:
Anniversaries of death

Cuban pool player (1863–1948)

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