Antoine Baumé
(1728-1804)

French chemist (1728-1804) – Antoine Baumé was born in Senlis (Commune in Oise, France) on February 26th, 1728 and died in Paris (Capital of France) on October 15th, 1804 at the age of 76. Today Antoine Baumé would be 296 years old.

Age

how old was Antoine Baumé when he died?

76

Antoine Baumé died in 1804 at the age of 76.


Biographical data

Birthday February 26th, 1728 (Thursday)
Place of Birth Senlis
Commune in Oise, France
Death Date October 15th, 1804 (Monday)
Death place Paris
Capital of France
Birth sign (Zodiac) Pisces (The Fish) ♓
Chinese Zodiac Monkey 猴

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Antoine Baumé

Birthday

When was Antoine Baumé born?

Antoine Baumé was born on February 26th, 1728.

Death

When did Antoine Baumé die?

Antoine Baumé died on October 15th, 1804 at the age of 76 in Paris (Capital of France). Today Antoine Baumé would be 296 years old.

Place of Birth

Where was Antoine Baumé born?

Senlis (Commune in Oise, France).

Death place

Where did Antoine Baumé die?

Paris (Capital of France).

Zodiac

What is the zodiac sign of Antoine Baumé?

Antoine Baumé was born in the zodiac sign Pisces (The Fish).

Chinese Zodiac

Which Chinese zodiac sign does Antoine Baumé have?

Antoine Baumé was born in 1728 in the year of the Chinese zodiac Monkey.

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Died on October 15th, 1804:
Anniversaries of death

French chemist (1728-1804)

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