Armand Salacrou
(1899-1989)

French dramatist (1899-1989) – Armand Salacrou was born in Rouen (Commune in Seine-Maritime, France) on August 9th, 1899 and died in Le Havre (Commune in Seine-Maritime, France) on November 23rd, 1989 at the age of 90. Today Armand Salacrou would be 124 years old.

Age

how old was Armand Salacrou when he died?

90

Armand Salacrou died in 1989 at the age of 90.


Biographical data

Birthday August 9th, 1899 (Wednesday)
Place of Birth Rouen
Commune in Seine-Maritime, France
Death Date November 23rd, 1989 (Thursday)
Death place Le Havre
Commune in Seine-Maritime, France
Birth sign (Zodiac) Leo (The Lion) ♌
Chinese Zodiac Pig 豬

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Also born in 1899

Armand Salacrou

Birthday

When was Armand Salacrou born?

Armand Salacrou was born on August 9th, 1899.

Death

When did Armand Salacrou die?

Armand Salacrou died on November 23rd, 1989 at the age of 90 in Le Havre (Commune in Seine-Maritime, France). Today Armand Salacrou would be 124 years old.

Place of Birth

Where was Armand Salacrou born?

Rouen (Commune in Seine-Maritime, France).

Death place

Where did Armand Salacrou die?

Le Havre (Commune in Seine-Maritime, France).

Zodiac

What is the zodiac sign of Armand Salacrou?

Armand Salacrou was born in the zodiac sign Leo (The Lion).

Chinese Zodiac

Which Chinese zodiac sign does Armand Salacrou have?

Armand Salacrou was born in 1899 in the year of the Chinese zodiac Pig.

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Died on November 23rd, 1989:
Anniversaries of death

French dramatist (1899-1989)

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