Armand Trousseau
(1801-1867)

French physician (1801-1867) – Armand Trousseau was born in Tours (City and commune in Indre-et-Loire, Centre-Val de Loire, France) on October 14th, 1801 and died in Paris (Capital of France) on June 23rd, 1867 at the age of 65. Today Armand Trousseau would be 222 years old.

Age

how old was Armand Trousseau when he died?

65

Armand Trousseau died in 1867 at the age of 65.


Biographical data

Birthday October 14th, 1801 (Wednesday)
Place of Birth Tours
City and commune in Indre-et-Loire, Centre-Val de Loire, France
Death Date June 23rd, 1867 (Sunday)
Death place Paris
Capital of France
Birth sign (Zodiac) Libra (The Scales) ♎
Chinese Zodiac Rooster 雞

Other personalities born on October 14

Also born in 1801

Armand Trousseau

Birthday

When was Armand Trousseau born?

Armand Trousseau was born on October 14th, 1801.

Death

When did Armand Trousseau die?

Armand Trousseau died on June 23rd, 1867 at the age of 65 in Paris (Capital of France). Today Armand Trousseau would be 222 years old.

Place of Birth

Where was Armand Trousseau born?

Tours (City and commune in Indre-et-Loire, Centre-Val de Loire, France).

Death place

Where did Armand Trousseau die?

Paris (Capital of France).

Zodiac

What is the zodiac sign of Armand Trousseau?

Armand Trousseau was born in the zodiac sign Libra (The Scales).

Chinese Zodiac

Which Chinese zodiac sign does Armand Trousseau have?

Armand Trousseau was born in 1801 in the year of the Chinese zodiac Rooster.

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Died on June 23rd, 1867:
Anniversaries of death

French physician (1801-1867)

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