Austin Blair
(1818-1894)

American politician (1818-1894) – Austin Blair was born in Caroline (Town in Tompkins County, New York, USA) on February 8th, 1818 and died in Jackson (City in Jackson County, Michigan, United States) on August 6th, 1894 at the age of 76. Today Austin Blair would be 206 years old.

Age

how old was Austin Blair when he died?

76

Austin Blair died in 1894 at the age of 76.


Biographical data

Birthday February 8th, 1818 (Sunday)
Place of Birth Caroline
Town in Tompkins County, New York, USA
Death Date August 6th, 1894 (Monday)
Death place Jackson
City in Jackson County, Michigan, United States
Birth sign (Zodiac) Aquarius (The Water-Bearer) ♒
Chinese Zodiac Tiger 兎

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Also born in 1818

Austin Blair

Birthday

When was Austin Blair born?

Austin Blair was born on February 8th, 1818.

Death

When did Austin Blair die?

Austin Blair died on August 6th, 1894 at the age of 76 in Jackson (City in Jackson County, Michigan, United States). Today Austin Blair would be 206 years old.

Place of Birth

Where was Austin Blair born?

Caroline (Town in Tompkins County, New York, USA).

Death place

Where did Austin Blair die?

Jackson (City in Jackson County, Michigan, United States).

Zodiac

What is the zodiac sign of Austin Blair?

Austin Blair was born in the zodiac sign Aquarius (The Water-Bearer).

Chinese Zodiac

Which Chinese zodiac sign does Austin Blair have?

Austin Blair was born in 1818 in the year of the Chinese zodiac Tiger.

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Died on August 6th, 1894:
Anniversaries of death

American politician (1818-1894)

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