Austin Daye (35)
June 5th, 1988
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American basketball player – Austin Daye was born in Irvine (City in Orange County, California, United States) on June 5th, 1988 and is 35 years old today.
Age
How old is Austin Daye?
35
Austin Daye is 35 years old.
Biographical data
| Birthday | June 5th, 1988 (Sunday) |
|---|---|
| Place of Birth | Irvine City in Orange County, California, United States |
| Birth sign (Zodiac) | Gemini (The Twins) ♊ |
| Chinese Zodiac | Dragon 龍 |
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_-_Cathy_Reed.jpg "Cathy Reed"){kind=small}
_(cropped).jpg "Nick Kroll")
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_-_Purich.JPG "Natasha Purich"){kind=small}
.jpg "Sophie Lowe")
Also born in 1988
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Austin Daye
Birthday
When was Austin Daye born?
Austin Daye was born on June 5th, 1988.
Place of Birth
Where was Austin Daye born?
Irvine (City in Orange County, California, United States).
Zodiac
What is the zodiac sign of Austin Daye?
Austin Daye was born in the zodiac sign Gemini (The Twins).
Chinese Zodiac
Which Chinese zodiac sign does Austin Daye have?
Austin Daye was born in 1988 in the year of the Chinese zodiac Dragon.
Austin Daye: Future birthdays
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