Benoît Rouquayrol
(1826-1875)

Benoît Rouquayrol
Benoît Rouquayrol Foto: Musée du Scaphandre, Espalion / CC BY-SA 4.0

French inventor (1826-1875) – Benoît Rouquayrol was born in Espalion (Commune in Aveyron, France) on June 13th, 1826 and died in Rodez (Commune in Aveyron, France) on November 14th, 1875 at the age of 49. Today Benoît Rouquayrol would be 197 years old.

Age

how old was Benoît Rouquayrol when he died?

49

Benoît Rouquayrol died in 1875 at the age of 49.


Biographical data

Birthday June 13th, 1826 (Tuesday)
Place of Birth Espalion
Commune in Aveyron, France
Death Date November 14th, 1875 (Sunday)
Death place Rodez
Commune in Aveyron, France
Birth sign (Zodiac) Gemini (The Twins) ♊
Chinese Zodiac Dog 狗

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Benoît Rouquayrol

Birthday

When was Benoît Rouquayrol born?

Benoît Rouquayrol was born on June 13th, 1826.

Death

When did Benoît Rouquayrol die?

Benoît Rouquayrol died on November 14th, 1875 at the age of 49 in Rodez (Commune in Aveyron, France). Today Benoît Rouquayrol would be 197 years old.

Place of Birth

Where was Benoît Rouquayrol born?

Espalion (Commune in Aveyron, France).

Death place

Where did Benoît Rouquayrol die?

Rodez (Commune in Aveyron, France).

Zodiac

What is the zodiac sign of Benoît Rouquayrol?

Benoît Rouquayrol was born in the zodiac sign Gemini (The Twins).

Chinese Zodiac

Which Chinese zodiac sign does Benoît Rouquayrol have?

Benoît Rouquayrol was born in 1826 in the year of the Chinese zodiac Dog.

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Died on November 14th, 1875:
Anniversaries of death

French inventor (1826-1875)

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