Charles F. Lettow (83)
February 10th, 1941

American judge – Charles F. Lettow was born in Iowa Falls (City in Hardin County, Iowa, United States) on February 10th, 1941 and is 83 years old today.

Age

How old is Charles F. Lettow?

83

Charles F. Lettow is 83 years old.


Biographical data

Birthday February 10th, 1941 (Monday)
Place of Birth Iowa Falls
City in Hardin County, Iowa, United States
Birth sign (Zodiac) Aquarius (The Water-Bearer) ♒
Chinese Zodiac Snake 蛇

Other personalities born on February 10

Also born in 1941

Charles F. Lettow

Birthday

When was Charles F. Lettow born?

Charles F. Lettow was born on February 10th, 1941.

Place of Birth

Where was Charles F. Lettow born?

Iowa Falls (City in Hardin County, Iowa, United States).

Zodiac

What is the zodiac sign of Charles F. Lettow?

Charles F. Lettow was born in the zodiac sign Aquarius (The Water-Bearer).

Chinese Zodiac

Which Chinese zodiac sign does Charles F. Lettow have?

Charles F. Lettow was born in 1941 in the year of the Chinese zodiac Snake.

Charles F. Lettow: Future birthdays

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