Charles Lebouc
(1822-1893)

Charles Lebouc
Charles Lebouc French cellist Charles Lebouc (1822-1893) Foto: Unattributed / Public Domain

French cellist (1822-1893) – Charles Lebouc was born in Besançon (Commune in Doubs, France) on December 22nd, 1822 and died in Hyères (Commune in Var, France) on March 6th, 1893 at the age of 70. Today Charles Lebouc would be 201 years old.

Age

how old was Charles Lebouc when he died?

70

Charles Lebouc died in 1893 at the age of 70.


Biographical data

Birthday December 22nd, 1822 (Sunday)
Place of Birth Besançon
Commune in Doubs, France
Death Date March 6th, 1893 (Monday)
Death place Hyères
Commune in Var, France
Birth sign (Zodiac) Capricorn (The Sea-Goat) ♑
Chinese Zodiac Horse 馬

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Charles Lebouc

Birthday

When was Charles Lebouc born?

Charles Lebouc was born on December 22nd, 1822.

Death

When did Charles Lebouc die?

Charles Lebouc died on March 6th, 1893 at the age of 70 in Hyères (Commune in Var, France). Today Charles Lebouc would be 201 years old.

Place of Birth

Where was Charles Lebouc born?

Besançon (Commune in Doubs, France).

Death place

Where did Charles Lebouc die?

Hyères (Commune in Var, France).

Zodiac

What is the zodiac sign of Charles Lebouc?

Charles Lebouc was born in the zodiac sign Capricorn (The Sea-Goat).

Chinese Zodiac

Which Chinese zodiac sign does Charles Lebouc have?

Charles Lebouc was born in 1822 in the year of the Chinese zodiac Horse.

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Died on March 6th, 1893:
Anniversaries of death

French cellist (1822-1893)

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