Charles Seignobos
(1854-1942)

French historian (1854-1942) – Charles Seignobos was born in Lamastre (Commune in Ardèche, France) on September 10th, 1854 and died in Ploubazlanec (Commune in Côtes-d'Armor, France) on April 24th, 1942 at the age of 87. Today Charles Seignobos would be 169 years old.

Age

how old was Charles Seignobos when he died?

87

Charles Seignobos died in 1942 at the age of 87.


Biographical data

Birthday September 10th, 1854 (Sunday)
Place of Birth Lamastre
Commune in Ardèche, France
Death Date April 24th, 1942 (Friday)
Death place Ploubazlanec
Commune in Côtes-d'Armor, France
Birth sign (Zodiac) Virgo (The Maiden) ♍
Chinese Zodiac Tiger 兎

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Also born in 1854

Charles Seignobos

Birthday

When was Charles Seignobos born?

Charles Seignobos was born on September 10th, 1854.

Death

When did Charles Seignobos die?

Charles Seignobos died on April 24th, 1942 at the age of 87 in Ploubazlanec (Commune in Côtes-d'Armor, France). Today Charles Seignobos would be 169 years old.

Place of Birth

Where was Charles Seignobos born?

Lamastre (Commune in Ardèche, France).

Death place

Where did Charles Seignobos die?

Ploubazlanec (Commune in Côtes-d'Armor, France).

Zodiac

What is the zodiac sign of Charles Seignobos?

Charles Seignobos was born in the zodiac sign Virgo (The Maiden).

Chinese Zodiac

Which Chinese zodiac sign does Charles Seignobos have?

Charles Seignobos was born in 1854 in the year of the Chinese zodiac Tiger.

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Died on April 24th, 1942:
Anniversaries of death

French historian (1854-1942)

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