Australian explorer (1795-1869) – Charles Sturt was born in Bengal (Historical and geographical region in the east region of the Indian subcontinent) on April 28th, 1795 and died in Cheltenham (Town in Gloucestershire, England) on June 16th, 1869 at the age of 74. Today Charles Sturt would be 228 years old.
Charles Sturt died in 1869 at the age of 74.
Birthday | April 28th, 1795 (Tuesday) |
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Place of Birth | Bengal Historical and geographical region in the east region of the Indian subcontinent |
Death Date | June 16th, 1869 (Wednesday) |
Death place | Cheltenham Town in Gloucestershire, England |
Birth sign (Zodiac) | Taurus (The Bull) ♉ |
Chinese Zodiac | Rabbit 兔 |
Charles Sturt was born on April 28th, 1795.
Charles Sturt died on June 16th, 1869 at the age of 74 in Cheltenham (Town in Gloucestershire, England). Today Charles Sturt would be 228 years old.
Bengal (Historical and geographical region in the east region of the Indian subcontinent).
Cheltenham (Town in Gloucestershire, England).
Charles Sturt was born in the zodiac sign Taurus (The Bull).
Charles Sturt was born in 1795 in the year of the Chinese zodiac Rabbit.