American politician (1820-1890) – David Wilber was born in Quaker Street (Human settlement in Schenectady County, New York, United States of America) on October 5th, 1820 and died in Oneonta (City in Otsego County, New York, United States) on April 1st, 1890 at the age of 69. Today David Wilber would be 203 years old.
David Wilber died in 1890 at the age of 69.
Birthday | October 5th, 1820 (Thursday) |
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Place of Birth | Quaker Street Human settlement in Schenectady County, New York, United States of America |
Death Date | April 1st, 1890 (Tuesday) |
Death place | Oneonta City in Otsego County, New York, United States |
Birth sign (Zodiac) | Libra (The Scales) ♎ |
Chinese Zodiac | Dragon 龍 |
David Wilber was born on October 5th, 1820.
David Wilber died on April 1st, 1890 at the age of 69 in Oneonta (City in Otsego County, New York, United States). Today David Wilber would be 203 years old.
Quaker Street (Human settlement in Schenectady County, New York, United States of America).
Oneonta (City in Otsego County, New York, United States).
David Wilber was born in the zodiac sign Libra (The Scales).
David Wilber was born in 1820 in the year of the Chinese zodiac Dragon.