Gustave Ramaciotti
(1861-1927)

Law clerk, theatrical manager, soldier (1861-1927) – Gustave Ramaciotti was born in Livorno (City in Italy, Central Italy) on March 13th, 1861 and died in Australia (Country in Oceania) on December 6th, 1927 at the age of 66. Today Gustave Ramaciotti would be 163 years old.

Age

how old was Gustave Ramaciotti when he died?

66

Gustave Ramaciotti died in 1927 at the age of 66.


Biographical data

Birthday March 13th, 1861 (Wednesday)
Place of Birth Livorno
City in Italy, Central Italy
Death Date December 6th, 1927 (Tuesday)
Death place Australia
Country in Oceania
Birth sign (Zodiac) Pisces (The Fish) ♓
Chinese Zodiac Rooster 雞

Other personalities born on March 13

Also born in 1861

Gustave Ramaciotti

Birthday

When was Gustave Ramaciotti born?

Gustave Ramaciotti was born on March 13th, 1861.

Death

When did Gustave Ramaciotti die?

Gustave Ramaciotti died on December 6th, 1927 at the age of 66 in Australia (Country in Oceania). Today Gustave Ramaciotti would be 163 years old.

Place of Birth

Where was Gustave Ramaciotti born?

Livorno (City in Italy, Central Italy).

Death place

Where did Gustave Ramaciotti die?

Australia (Country in Oceania).

Zodiac

What is the zodiac sign of Gustave Ramaciotti?

Gustave Ramaciotti was born in the zodiac sign Pisces (The Fish).

Chinese Zodiac

Which Chinese zodiac sign does Gustave Ramaciotti have?

Gustave Ramaciotti was born in 1861 in the year of the Chinese zodiac Rooster.

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Died on December 6th, 1927:
Anniversaries of death

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Law clerk, theatrical manager, soldier (1861-1927)